Utility Maximization

A consumer maximizes utility when:
  1. `MRS = MRT`
  2. `Xp_X + Yp_Y = I`

Example

Alice buys chocolate (X) for `p_X = $4` and strawberries (Y) for `p_Y = $2`. Her budget is `I = $12`. Her utility is measured by `u \left( X, Y \right) = X Y^2`.

Step 1: MRS = MRT

$$ \begin{align*} MRS &= MRT \\ -\frac{MU_X}{MU_Y} &= -\frac{p_X}{p_Y} \\ -\frac{Y^2}{2XY} &= -\frac{2}{4} \\ - \frac{Y}{2X} &= - \frac{2}{4} \\ Y &= X \end{align*} $$

Step 2: Plug back in the budget

$$ \begin{align*} Xp_X + Yp_Y &= I \\ 4X + 2Y &= 12 \\ 4X + 2X &= 12 \\ 6X &= 12 \\ X &= 2 \end{align*} $$

Step 3: Conclude

Alice will buy 2 chocolates and 2 strawberries.

Question

Alice's utility function is `u \left( X, Y \right) = 6 X^{{20}} Y^{{24}}`..

.

The price of chocolate (X) is `p_X = $10`, and the price of strawberry Y is `p_Y = $8`. Alice has in her pocket `I = $440`.

What quantities X and Y maximizes Alice's utility?

Alice will buy 20 chocolates and 30 strawberries.

Step 1: MRS = MRT

$$ \begin{align*} MRS &= MRT \\ -\frac{MU_X}{MU_Y} &= -\frac{p_X}{p_Y} \\ \frac{6 \times 20 X^{19} Y^{24}}{6 \times 24 X^{20} Y^{23}} &= \frac{10}{8} \\ \frac{20 Y}{24 X} &= \frac{10}{8} \\ \frac{Y}{X} &= \frac{10 \times 24}{8 \times 20} \\ \frac{Y}{X} &= \frac{3}{2} \\ \frac{Y}{X} &= 1.5 \\ Y &= 1.5 X \end{align*} $$

Step 2: Plug back in the budget

$$ \begin{align*} 10 X + 8 Y = 440 \\ 10 X + 8 \times 1.5 X = 440 \\ \left( 10 + 8 \times 1.5 \right) X = 440 \\ 22.0 X = 440 \\ X = \frac{440}{22.0} \\ X = 20 \end{align*} $$

Step 3: Conclude

`X=20` and `Y = 1.5 X = 30`